Bar Bending Schedule for 'RCC' Beam

Bar bending schedule is also known as bar schedule, In this article, we will calculate bars for reinforcement concrete beam.

bar schedule

We will take one simple example of reinforcement quantity calculations for a concrete beam. Consider a beam of the clear length of 6550mm, 250mm wide by 450mm depth. It consists of 2-20 and 1-12 diameter bars at the top, 2-25, and 1-20 diameter bars at the bottom. Diameter of stirrup is 10mm spaced at 150mm/ 200mm/ 150mm center to center. Clear cover to reinforcement provided is 25mm and lap length is 45d.

detail of main beam (MB16)

bar bending schedule

main beam 16 drawing detail

Now we will calculate the length of reinforcement based on shapes of reinforcement required for reinforced concrete beam in the above example.

We will start with top reinforcement,

Bar mark, 92

Bar shape of 92 is as shown below,

92, bar mark-bar shape

Length of 92 = clear distance on drawing detail + bend length

= 2150 + 200 = 2350

Bend length = consider as 200mm

Bar mark, 93

Bar shape of 93 is as shown below:

93, bar mark-bar shape

Length of 93 = clear distance on drawing + 2 (lap length*)

= (6500 - 2 x 2150) + 2 x 550
= 3300

*lap length = 45d = 45 x 12 = 540 = consider as 550mm

Now we can calculate bottom reinforcement of concrete beam,

Bar mark, 94

Bar shape of 94 is as shown below:

94, bar mark-bar shape

where can take 6000mm (6m) full bar and 90º bend bar

Length of 94 = Bend length + lap length* + balance length of full bar

= 200 + 1150 + (6000-{200+ 1150})

= 200 + 1150 + 4650 = 6000

*lap length = 45d = 45 x 25 = 1125 = consider as 1150mm

&

Length of 90º bend bar = bend length + balance length of the beam

= 200 + (6500 - 4650- 20) = 1830

Bar mark, 95

Bar shape of 95 is as shown below:

95, bar mark-bar shape

Length of 95 = 6500 - (2 x 300 + 2 x 200)
= 5500

Length of Stirrups

Bar mark, 96

Stirrups are spaced at 150mm/ 200mm/ 150mm center to center. Stirrups are provided between walls or support for a beam.

section x-x of main beam 16

No. of stirrups required for given beam = 6500/200 = 33

Length a = 450 – 2 x 25 – 10 = 390mm

Length b = 250 – 2 x 25 – 10 = 190mm

Therefore length of one stirrup = 2 x (390 + 190) + 90* = 1250 mm

* Where 90mm is the minimum hook length as per IS 2502 – Table – II.